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If human Place vacation is proscribed from the G power vulnerability, is there a method to counter G forces? 26
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James JenkinsJames Jenkins 27.2k2323 gold badges108108 silver badges242242 bronze badges $endgroup$ three four $begingroup$ "1g of thrust" pointed straight up will equilibrium gravity, and result in you floating. "1g" (as I go through it), could be the acceleration caused by the Earth's gravity; if that's how you actually determine it, then your acceleration decreases as you get more (and 'come to feel a lot less pull') from Earth.
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if we allow ourselves to believe a=9.8m/s/s, then it's actually not depended on mass, so relativity is just not a huge issue. $endgroup$
But that point is within the viewpoint of stationary observers in the departure level. The excursion's length with the traveler's viewpoint could well be less as a result of here time dilation result predicted by Einstein's Concept of Relativity. The increased the gap, the increased the speed from your stationary observer's viewpoint.
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one $begingroup$ @Mark not pretty true. In the end, should you observe things slipping in frequent gravity, you still can not see them transcend pace of light, meaning that Newtonian physics doesn't keep whilst noticed from the ship. $endgroup$
HopDavidHopDavid 16k4444 silver badges8080 bronze badges $endgroup$ 9 twenty $begingroup$ Your "incorporate a little more than the usual yr for every lightyear distance" is correct for an out of doors observer, but for someone aboard the ship, the Newtonian design is right for all distances (as calculated before starting acceleration): Lorentz contraction will shrink the universe during journey to present the appearance of Newtonian physics. $endgroup$
Mainly because of the time dilation impact, 1G acceleration need to be sufficient to journey any where in our galaxy in under a life time from the viewpoint in the traveler, but not the stationary observer. To learn more on some time dilation impact read through Stephen Hawking's "Transient Record of Time"